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Chapter 9: The Normal Probability Distribution

385

Figure 9-25:

Area and probability value for

P

(1.5 ≤

z

2.5)

An alternative solution to the problem if we use the standard normal

distribution would be to use the table for

-values between zero and some

other

-value. This is equivalent to finding

P

(1.5

2.5) =

P

(0

2.5) -

P

(0

1.5). From this standard normal table, for

=

2.5, the corresponding value is 0.4938, and for

= 1.5, the corresponding

value is 0.4332. Thus, the required area for

P

(1.5

2.5) =

P

(0

2.5) -

P

(0

1.5) = 0.4938 – 0.4332 = 0.0606. This is shown

Figure 9-26

.

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