Chapter 9: The Normal Probability Distribution
385
Figure 9-25:
Area and probability value for
P
(1.5 ≤
z
≤
2.5)
An alternative solution to the problem if we use the standard normal
distribution would be to use the table for
-values between zero and some
other
-value. This is equivalent to finding
P
(1.5
2.5) =
P
(0
2.5) -
P
(0
1.5). From this standard normal table, for
=
2.5, the corresponding value is 0.4938, and for
= 1.5, the corresponding
value is 0.4332. Thus, the required area for
P
(1.5
2.5) =
P
(0
2.5) -
P
(0
1.5) = 0.4938 – 0.4332 = 0.0606. This is shown
Figure 9-26
.
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