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Chapter 11: Confidence Intervals – Large Samples

485

Example 11-7:

The Student President of a large regional university wishes

to estimate the average distance commuting students’ travel to the campus.

A sample of 49 students was randomly selected and yielded a mean of 42

miles and a standard deviation of 7 miles. Construct a 99% confidence

interval estimate for the true mean distance commuting students travel to the

campus. Assume that the population of commuting distances by the students

is normally distributed.

Solution:

Given

= 0.01,

= 2.5758,

̅

= 42,

= 49,

= 7, and

̅

= 1.0. Thus the 99% confidence interval estimate for the mean

distance, using the formula, is 42

2.5758

1.0 = 42

2.5758. That is, we

are 99% confident that the average distance commuting students travel to the

campus will lie between 39.4242 miles and 44.5758 miles.

Again, we can use the

Large Sample Confidence Interval for a Single

Population Mean

workbook to help with the computations. However we

will have to use the portion of the workbook which assumes that the

population standard deviation is unknown.

Figure 11- 11

shows the output

with the 99% confidence interval. Observe that the 99% confidence interval

is the same as the interval computed by the formula.