Table of Contents Table of Contents
Previous Page  402 / 762 Next Page
Basic version Information
Show Menu
Previous Page 402 / 762 Next Page
Page Background

402

Chapter 9: The Normal Probability Distribution

Thus applying the correction factor gives the following equivalence:

P

(

X

= 50)

P

(49.5

X

50.5).

Figure 9-38

shows how you will apply the correction factor for all possible

scenarios for a value of 50. Note that the center point of the bar of the

histogram represents where the discrete value of 50 is located.

Figure 9-38:

P

(

X

= 50) =

P

(49.5

X

50.5)

Case 2: P(X

a

) where

a

is the value of a Binomial random

variable X

If we needed to find P(

X

50) when

X

is a binomial random variable then

we will have to apply the continuity correction factor in order to use the

normal approximation since

X

is discrete. Since

X

= 50 is included

in

X

50, then we have to move 0.5 to the left of 50 to compute the

probability

P

(

X

50), in order to include the value of 50 in the computation.

Thus applying the correction factor gives the following equivalence:

P

(

X

50) ≡

P(X

49.5).