Chapter 4: Measures of Position
149
Figure 4-1:
Computed Mean and Standard Deviation
for
Example 4-1
Thus the
-score for the sample value of 18 is:
-score = (18 – 14.25)/2.6592 = 1.4102 (to four decimal places)
Thus the
-score is approximately equal to 1.41. That is, the data value of
18 will be located approximately 1.41 standard deviations
above
the mean
of 14.25, since the
-score is positive.
We can also use the
Basic Statistics
workbook to directly give the result.
The workbook result is shown in
Figure 4-2
.
Click here for the Basic Statistics Workbook




