523 / 762
Chapter 12: Hypothesis Tests – Large Samples
523
Solution:
0.43
0.43
:
=
√
= (65 - 100
0.43)/4.95076 = 4.4438.
: For a significance level of
= 0.05, reject the null hypothesis if the
computed test statistic value
= 4.4438 > +
= 1.645.
Conclusion:
Since 4.4438 > 1.645, then the null hypothesis
will be
rejected. That is, there is sufficient sample evidence to claim that more than
43% of adults ate two full meals per day at the 5% level of significance
Note:
This means that there is a significant difference between the sample
proportion of 65/100 = 0.65 and the postulated proportion of 0.43.
Figure 12-3
displays the test statistic in relation to the rejection region.
Observe that the test statistic falls to the far right in the rejection region.