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Chapter 12: Hypothesis Tests – Large Samples
Conclusion:
Since
P
-value = 0.0000 <
= 0.05, then the null hypothesis
will be rejected. That is, there is sufficient sample evidence to claim that
more than 43% of adults ate two full meals per day at the 5% level of
significance
(b) Left –tailed (one-tailed) Test
(where
is a specified proportion value)
√
: For a specified significance level
, reject the null hypothesis
if the computed test statistic value
is less than -
.
Conclusion
: ……….
Note:
This is a left-tailed test because the direction of the inequality sign in
is to the left.
Example 12-3:
Your professor would like to establish that less than 5% of
the student population on your campus is left handed. In a random sample
of 120, 10 of the students said that they were left handed. Test at the 1%
level of significance.
Summary Information:
n
=120,
x
(number of successes) = 10,
= 0.01,
= 2.33, and
= 0.05 (5%). Also,
√
= 2.3875.
Since the professor would like to establish that less than 5% of the student
population on your campus is left handed, the alternative hypothesis should
reflect this.
Solution:
0.05
0.05