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Chapter 12: Hypothesis Tests – Large Samples

557

Summary information

:

Let

be the proportion of the 18 – 24 age group

without health insurance. Let

be the proportion of the 35 – 44 age group

without health insurance. From the information given,

= 75,

= 100,

̂

=

= 0.6667,

̂

=

= 0.45,

̂

=

=

= 0.5429,

= 0.01,

=

= 2.576.

Solution:

:

(

)

:

(

)

̂

̂

√ ̂ ̂ (

)

= 2.8517

D.R:

For a significance level

= 0.01, reject the null hypothesis if | 2.8517 |

= 2.8517 >

= 2.576.

Conclusion

:

Since 2.8517 > 2.576, reject

. There is sufficient sample

evidence to conclude that the proportion of those without health insurance

was significantly different between the 18 – 24 age group and the 35 – 44

age group, at the 1% level of significance.

Note:

There is a significant difference between the difference between the

sample proportions and the postulated value of 0.

Figure 12-23

displays the test statistic in relation to the rejection region.

Observe that the test statistic falls in the rejection region.