698 / 762
698
Chapter 15: Chi-Square Tests
Table 15-14:
Table with the computations for the
test
statistic
Note that the degrees of freedom for the test
= 5 – 1 = 4,
= 0.05, and
= 9.488. Using this information for the test, we have:
: The distribution of the proportions of the leading digits for the
heights of the tallest structure is the distribution described by
Benford’s law. That is
= 0.301 and
= 0.179 and
= 0.125 and
= 0.301 and
= 0.301.
: At least one of the proportions of the leading digits for the heights of
the tallest structures specified by Benford’s law is different from the
rest.
.:
= 0.8681
.: For a level of significance
= 0.05, reject
if the computed test
statistic
= 0.8681 >
= 9.488.
Conclusion
: Since 0.8681 < 9.488 do not reject
H
0
. That is, there is
insufficient evidence to conclude that at least one of the proportions of the
leading digits for the heights of the tallest structures is different from those
specified by Benford’s Law. That is, the deviations of the percentages in
the observed values are not significantly different from those specified by
Benford’s Law.